5^2+4^2=c^2

Solution for 5^2+4^2=c^2 equation:

5^2+4^2=c^2

We move all terms to the left:

5^2+4^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+41=0

a = -1; b = 0; c = +41;
Δ = b2-4ac
Δ = 02-4·(-1)·41
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{41}}{2*-1}=\frac{0-2\sqrt{41}}{-2}
=-\frac{2\sqrt{41}}{-2}
=-\frac{\sqrt{41}}{-1}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{41}}{2*-1}=\frac{0+2\sqrt{41}}{-2}
=\frac{2\sqrt{41}}{-2}
=\frac{\sqrt{41}}{-1}
$